x^2+4.25x-36.125=0

Solution for x^2+4.25x-36.125=0 equation:

x^2+4.25x-36.125=0

a = 1; b = 4.25; c = -36.125;
Δ = b2-4ac
Δ = 4.252-4·1·(-36.125)
Δ = 162.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.25)-\sqrt{162.5625}}{2*1}=\frac{-4.25-\sqrt{162.5625}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.25)+\sqrt{162.5625}}{2*1}=\frac{-4.25+\sqrt{162.5625}}{2}
$